1.

a body possesses an initial velocity of 5 m/s and moves with a uniform acceleration of 2 ms-2. calculate the distance moved by the body in 4s.​

Answer»

ion :Given :▪ Initial velocity of BODY = 5mps▪ Acceleration of body = 2m/s^2▪ TIME INTERVAL = 4sTo Find :▪ DISTANCE covered by body in the given interval.Concept :✒ Here acceleration is CONSTANT throughout the whole journey so we can apply equation of kinematics directly.✒ Third equation of kinematics is given by☞ S = ut + (1/2)at^2S denotes distanceu denotes initial velocitya denotes accelerationt denotes time intervalCalculation :→ S = (5×4) + (1/2)×2×(4)^2→ S = 20 + 16→ S = 36m



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