1.

a body on which a firce 5i^ +4j^ + 10k^ netwon acts is displaces from 2i^ +5j^ + 4k^ meter to 7i^+7j^ +8k^ meter. what is the kinetic energy gained by the body​

Answer»

Displacement = (7i^+7j^ +8k^) - (2i^ +5j^ + 4k^) = 5i^ + 2j^ + 4k^Kinetic ENERGY gained = WORK done                                        =  F . s                                       = (5i^ +4j^ + 10k^). ( 5i^ + 2j^ + 4k^)                                       = 25 + 8 + 40 = 73



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