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a body on which a firce 5i^ +4j^ + 10k^ netwon acts is displaces from 2i^ +5j^ + 4k^ meter to 7i^+7j^ +8k^ meter. what is the kinetic energy gained by the body |
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Answer» Displacement = (7i^+7j^ +8k^) - (2i^ +5j^ + 4k^) = 5i^ + 2j^ + 4k^Kinetic ENERGY gained = WORK done = F . s = (5i^ +4j^ + 10k^). ( 5i^ + 2j^ + 4k^) = 25 + 8 + 40 = 73 |
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