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A body of mass30×10−3kg, when acted upon by a force for 5s, attains a velocity of 100 m/s. If the same force is applied for 2 minutes on a body of mass 10 kg at rest, what will be its velocity? |
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Answer» or First bodyMass of body, m₁= 30×10⁻³ kgTime for which force is applied, t₁= 5sInitial velocity, u₁= 0Final velocity, v₁= 100 m/sFor Second bodyMass of body, m₂= 10 kgTime for which force is applied, t₂= 2min= 120sInitial velocity, u₂= 0To Find:FINAL velocity of second bodySolution:We know that,For a body moving in uniform motion or having constant ACCELERATION, acceleration 'a' of body is given by where, V is final velocity U is initial velocity t is time takenForce=mass×accelerationLet the acceleration produced in first body after applying force be aSo, Let the force applied on first body be FSo,Let the acceleration of second body after applying same force be a'So,Also, let the final velocity of second body be v₂So, Hence, the final velocity of second body is 7.2 m/s. |
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