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A body of mass m hung at one end of the spring executes SHM. where K is the force constant of the spring. prove that the relation given below is incorrect, alsoderive correct relation.T= 2πm/K​

Answer»

HELLO FRIEND HERE'S UR ANSWERExplanation:ANSWER : Cmk−−−√Solution : The given equation is T=2πmk Taking the dimensions of both sides, we have [T]=[M][ML0T−2]=T2 As the dimensions of two sides are not equal , hence the equation is incorrect. Let the CORRECT relation be T=Cmakb,whereC is constant. Equating the dimensions of both sides , we get [T]=[M]a[MT−2]b or [M0L0T]=[Ma+bL0T−2b] Comparing the powers of M,L, and T on both sides , we get a+b=0and−2b=1. Therefore , b=−12anda=12 :. T=Cm−1/2k−1/2=Cmk−−−√ This is the correct equation.HOPE IT HELPS YOU FRIEND IF YOU LIKE ME ANSWER THEN PLEASE DROP A LIKE AND MARK ME AS BRAINLIEST



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