a body of mass 6 kg accelerats from 6 m/s to 18 m/s in 3 seconds due t

1.	a body of mass 6 kg accelerats from 6 m/s to 18 m/s in 3 seconds due to applicatuon of force on it .find out the magnitude of force
Answer» Step-by-step explanation: GIVEN, MASS of the BODY (m) = 6 kg Initial Velocity (U) =6 m/s Final velocity (v) = 18 m/s Time (t) = 3 seconds Now, From 1st equation of motion, v=u+at 18= 6+a.3 18-6= 3a 12=3a a=4 m/s² Now, F= ma = 6×4 = 24 N Therefore, the magnitude of FORCE is 24 N. Hope it helps :)

a body of mass 6 kg accelerats from 6 m/s to 18 m/s in 3 seconds due to applicatuon of force on it .find out the magnitude of force

Answer»

Step-by-step explanation:

GIVEN,

MASS of the BODY (m) = 6 kg

Initial Velocity (U) =6 m/s

Final velocity (v) = 18 m/s

Time (t) = 3 seconds

Now,

From 1st equation of motion,

v=u+at

18= 6+a.3

18-6= 3a

12=3a

a=4 m/s²

Now,

F= ma

= 6×4

= 24 N

Therefore, the magnitude of FORCE is 24 N.

Hope it helps :)

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a body of mass 6 kg accelerats from 6 m/s to 18 m/s in 3 seconds due to applicatuon of force on it .find out the magnitude of force​

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a body of mass 6 kg accelerats from 6 m/s to 18 m/s in 3 seconds due to applicatuon of force on it .find out the magnitude of force