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| 1. |
A body of mass 50g has a heat capacity of 3cal/°C. What will be the specific heat capacity of that body |
| Answer» LET subscript 1 denote solid (hot BODY) and subscript 2 denote water (cold body)Initial temp. of solid T₁=150°CMass of solid m₁ = 50 g = 0.05 KgInitial temp. of water T₂=11°CMass of water m₂= 100 g = 0.1 KgFinal temp of both T= 20°CSpecific HEAT capacity of water c₂=4.2 J/g°C Let Specific heat capacity of solid be c₁now,heat gained by water = heat lost by solidheat gained/lost = mcΔT∴ m₁c₁ΔT₁ = m₂c₂ΔT₂⇒ 0.05*c₁*(150-20) = 0.1*4.2*(20-11)⇒ 0.05*130*c₁ = 0.1*4.2*9⇒ c₁ = 0.5815 J/g°CAnswer: Specific heat capacity of the solid is 0.5815 J/g°C .Explanation: | |