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A body of mass 5 kg moving with a velocity of 100 ms-¹ is brought to rest by applying a force for 25 seconds.The magnitude of the applied force is |
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Answer» m= 5kgu= 100m/sv=0.t=25sF = maa= v-u/t = 0-100/25 = -4m/s^2Magnitude of force = ma= 5×4 = 20N(MAGNITUDE is always POSITIVE VALUE. So-20 is not correct) |
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