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a body of mass 5 kg changes it's velocity from 2 to5 in 4 seconds . calculate the rate of change to work done and force acting on the object​

Answer» TION:ANSWERHere, m=5 KG, u=5 MS −1 , v=10 ms −1 , t= 10sUsing v=u+at a= tv-u = 10S(10−5)ms −1 =0.5ms −2 As F=ma∴F=(5KG)(0.5ms −2 )=2.5N


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