Saved Bookmarks
| 1. |
A body of mass 4kg moving with velocity of 2.5m/s collides with a stationary body of mass0.2kg. if the two bodies stick together after collision. Calculate their common velocity after impact |
|
Answer» Explanation: Taking the 2 bodies as an isolated system, Law of conservation of momentum TELLS us that the total momentum will remain constant. According to the law, m1u1 + m2u2 = m1v1 + m2v2 But in this case, the bodies stick after collision. Since they are sticking, Their total mass after sticking = 4 + 0.2 = 4.2 kg Now, m1u1 + m2u2 = m3v3 => 4 x 2.5 + 0.2 x 0 = 4.2 x V3 => v3 = 10 / 4.2 => velocity after sticking = 2.38 m/s APPROX. |
|