1.

A body of mass 25g is under water at a depth of 50 cm. If the specific gravity of the material of the body is 5 and g = 980cm*s^(-2), find the amount of work required to lift it very slowly to the surface.

Answer»

SOLUTION :Volume of water displaced by the BODY = volume of the body = `25/5=5cm^(3)`
`therefore` Weight of displaced water = `5gxxg`
`therefore` Downward resultant FORCE
= `(25xx980-5xx980)=20xx980=19600`DYN
`therefore" "` Required WORK done = `19600xx50=9.8xx10^(5)`erg.


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