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A body of mass 25g is under water at a depth of 50 cm. If the specific gravity of the material of the body is 5 and g = 980cm*s^(-2), find the amount of work required to lift it very slowly to the surface. |
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Answer» SOLUTION :Volume of water displaced by the BODY = volume of the body = `25/5=5cm^(3)` `therefore` Weight of displaced water = `5gxxg` `therefore` Downward resultant FORCE = `(25xx980-5xx980)=20xx980=19600`DYN `therefore" "` Required WORK done = `19600xx50=9.8xx10^(5)`erg. |
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