Saved Bookmarks
| 1. |
A body of mass 20kg is at rest.A force of 5N is applied on it . Calculate the work done in the first second |
|
Answer» m = 20 kg F = 5 N t = 1 sec A = \(\frac{F}{m}=\frac{5}{20}=\frac{1}{4}\) m/s2 t = 1 sec now, work done = Fs. S = ut + 1/2 ut2 S = 1.125 m F = 5 x 1.125 = 5.625J |
|