1.

A body of mass 20kg is at rest.A force of 5N is applied on it . Calculate the work done in the first second

Answer»

m = 20 kg

 F = 5 N

t = 1 sec

A = \(\frac{F}{m}=\frac{5}{20}=\frac{1}{4}\) m/s2

t = 1 sec

now, work done = Fs.

S = ut + 1/2 ut2

S = 1.125 m

F = 5 x 1.125 = 5.625J



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