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A body of mass 20 kg moving with a speed of 10 ms -1 on a horizontal smooth surfacecollides with a massless spring of spring constant 5 N/m. If the mass stops aftercollision, distance of compression of the spring will be :(a)10 m(b)50 m(c)5 m(d)20 m |
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Answer» ANSWER:d 20 Explanation Law of MECHANICAL ENERGY conservation 1/2mv^2=1/2kx^2 20X 100/2=1/2X 5X x^2 x=20 |
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