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a body of mass 10 kg from rest accelerates uniformly to a speed of 30m/s in 10sec. Brakes are applied and the body stops in next 5 sec..calculate the accelerating force and stopping force.....plz answer.. ill mark brainliest |
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Answer» mass of body (m) = 10 kg INITIAL VELOCITY (u) = 0 m/s final velocity (v) = 30 m/s time taken = 10 SEC FIRST CASE :we have to find acceleration :by formula v = u + at putting values30 = 0 + 10 a30 = 10 a a = 30/10 hence , acceleration = 3 as we know , FORCE = mass . aceleration force = 10 . 3 force = 30 N SECOND CASE :AS car is MOVING with final velocity , in second case that velocity will be taken as initial .hence , initial velocity (u)= 30 m / s final velocity (v) = 0 m/s (as brakes are applied)time taken (t) = 5 secmass will be constant or same as 10 kg again , by formula v = u + at 0 = 30 + 5a 5a = - 30 a = - 30 / 5acceleration = - 6 now , force f = m.a f = 10.-6f = - 60 N hence, accelerating force = 30N stopping force = - 60 N hope it helps u !!! mark as brainliest plzz appreciate my hardwork mate ❤ |
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