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A body of mass 10 kg at rest is applied with perpendicular force of 4 N and 3 N at the same time, then at the end of 10 seconds its kinetic energy = ......... |
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Answer» Solution :RESULTANT force `F= [(4)^(2) + (3)^(2) ]^(1/2) =5` `a=(5)/(m ) = (5)/(10) = 0 .5 m//s^(2)` `v=v_(0) at` `v=0 + 0.5 xx 10` `v= 5m//s` `k=(1)/(2) mv^(2)` `=(1)/(2) xx 10 xx (5)^(2)` `=5 xx 25 ` `=125 J` |
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