A body of mass 0.5 kg experience a forceF = (2 + 3x2) N where x (in me

1.	A body of mass 0.5 kg experience a forceF = (2 + 3x2) N where x (in metre) is thedisplacement from origin. It is released to movealong x-axis from origin then its initial accelerationis(1) 2 m/s2(3) 4 m/s2(2) 10 m/s2(4) Zero
Answer» Explanation: F=ma a=F/m a=(2+3*2)/0.5 a=8/0.5 a=4m/s² i THINK it is HELPFUL..... mark me as brainlist.....

A body of mass 0.5 kg experience a forceF = (2 + 3x2) N where x (in metre) is thedisplacement from origin. It is released to movealong x-axis from origin then its initial accelerationis(1) 2 m/s2(3) 4 m/s2(2) 10 m/s2(4) Zero

Answer»

Explanation:

F=ma

a=F/m

a=(2+3*2)/0.5

a=8/0.5

a=4m/s²

i THINK it is HELPFUL.....

mark me as brainlist.....

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A body of mass 0.5 kg experience a forceF = (2 + 3x2) N where x (in metre) is thedisplacement from origin. It is released to movealong x-axis from origin then its initial accelerationis(1) 2 m/s2(3) 4 m/s2(2) 10 m/s2(4) Zero​

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A body of mass 0.5 kg experience a forceF = (2 + 3x2) N where x (in metre) is thedisplacement from origin. It is released to movealong x-axis from origin then its initial accelerationis(1) 2 m/s2(3) 4 m/s2(2) 10 m/s2(4) Zero