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A body of mass 0.2kg is moving with a velocity 4m/s to bring it to rest in 10min the work done is |
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Answer» M = 0.2 kg u = 4 m/s t = 10 min = 10 x 60 sec = 600 sec We know a = \(\frac{v-u}t\) = \(\frac{0-4}{600}\) = 0.006 m/s2 Then F = ma F = 0.2 x 0.006 F = 0.0012 N S = ut + \(\frac12\)at2 S = 4 x 600 + \(\frac12\) x \(\frac{0.006}{1000}\times600\times600\) S = 2400 + 180 S = 2580 m Work done W = F. 5 W = 0.0012 x 2580 W = 3.096 j |
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