Saved Bookmarks
| 1. |
A body of mass 0.25 kg moving with the velocity 12m/s is stopped by applying a force of 0.6n . Calculate the time taken to stop the body , also calculate the impulse of this force |
|
Answer» time=5 secand impulse = 3 kgm/s in opposite direction of motion.Explanation:When it STOPS the FINAL VELOCITY is zero so apply v=u+at(u=12m/s,v=0),Also impulse=mv-mu(that is change in MOMENTUM). |
|