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A body of density `rho` is dropped from reat from a height h into a lake of density `sigma(sigmagtrho)`. The maximum depth the body sinks inside the liquid is (neglect viscous effect of liquid)A. `((hsigma)/(rho-sigma))`B. `hsigma/(rho)`C. `h((rho)/(rho-sigma))`D. `h((rho)/sigma-1)` |
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Answer» Correct Answer - A If `v_(0)-sqrt(2gh)` is the velocity downwards just when the body enters the liquid the final velocity at the maximum depth it will sink is zero. Its acceleration is `a`. Hence `(-)y=` maximum depth `(v_(0)^(2))/(2a)=(2gh)/(2g(rho/sigma-1))` `:. Y=(hsigma)/(rho-sigma)` |
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