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A body moving with change in its position with time as x = (3t2 + 2t + 1 )m. what is the acceleration of the body at t = 5 sec |
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Answer» Given, X=t 2 −4t+6 So, the change in velocity is: dt dx =2t−4 SINCE velocity is changing, At t=0,x 1 =6 At t=2,x 2 =2 So the magnitude of the distance traveled is: 6−2=4m At t=3,x 3 =3 So distance traveled from t=2s to t=3s x 3 −x 2 =3−2=1m THUS the total distance is: 4+1=5mExplanation: |
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