1.

A body moves from rest with uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 seconds after the startAlso show the process

Answer»

Hii...
Here is your answer..

SOLUTION:-
UNIFORM Acceleration=0(as he STARTS from rest)
Distance=270m
Time=3sec
Acceleration=?

We'll FIND it by using equation,that is:-
= > s = ut + \frac{1}{2} a {t}^{2} \\ = > 270= 0 \times 3 + \frac{1}{2} \times a \times {(3)}^{2} \\ = > 270 = 0 \times \frac{1}{2} \times a \times 9
= > a = \frac{270 \times 2}{9} \\ = > a = \frac{540}{9}
= > a = 60m
Now,
Acceleration=60m/s
Final velocity after 10 sec=
= > a = \frac{(v - u)}{t} \\ = > 60 = \frac{(v - 0)}{10}
= > v = 60 \times 10 \\ = > v = 600
So,final velocity after 10 sec is 600m

Hope it helps uh...✌️✌️✌️


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