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a body moves from rest with a uniform acceleration of 470 cm in 6 seconds find its final velocity after 15 seconds |
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Answer» tion:Given :INITIAL velocity (U) = 0 m/s.Distance (s) = 470 TIME (t) = 6 secs.To find:Acceleration (a) =?Velocity after 15. sec Solution :We will use third equation of motion here;s = ut + 1/2 at²→ 270. 0 * 6+1/2 * a * 6 * 6→ 470 =. 36/2 a→ 36 a = 940⇒a= 940/36 ⇒a= 26 m/ s Now,We will use first equation of motion here;After 15 secs.V = u+ at v. = 0+ 26 * 15 v= 390 v= 390 m/s Hence,The final velocity acquired by the car is 390 m/s hope it helps you |
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