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A body moves along a circle of radius (20)/(pi)m with constant tangential acceleration . If the velocity of the body is 80 m/s at the end of the second revolution after motion has begun . Then calculate the tangential acceleration . |
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Answer» Solution :RADIUS `r = (20)/(pi) m` Velocity `v = 80 ms^(-1)` Initial angular velocity `omega(0) = 0` `omega = (r)/(omega)` `theta = 2 rev = 4 pi RAD` As `omega ^(2) + omega_(0)^(2) + 2 ALPHA theta` `((v)/(r))^(2) = 0^(2) + 2 ((a)/(r)) theta` `a = (v^(2))/(2 r theta)` `:. a = ((80)^(2))/(2 xx (20)/(pi) xx 4 pi) = 40 ms^(-2)` |
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