1.

A body is thrown horizontally with a velocity u from a tower of height h After how much time and at what distance from the base of the tower will the body strike the ground?

Answer»

Solution :Consider the VERTICAL motion `h=0+1/2"gt"^2 ,t=sqrt((2h)/G)` Horizontal displacement = Horizontal velocity X Time `=musqrt((2h)/g)`


Discussion

No Comment Found