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| 1. |
A body is thrown horizontally with a velocity u from a tower of height h After how much time and at what distance from the base of the tower will the body strike the ground? |
| Answer» Solution :Consider the VERTICAL motion `h=0+1/2"gt"^2 ,t=sqrt((2h)/G)` Horizontal displacement = Horizontal velocity X Time `=musqrt((2h)/g)` | |