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A body is released from the top of the tower height H. It takes t time to reach the ground. Whereis the body t÷2time after release :- |
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Answer» gt 2 At 2t ,s= 21 g(t/2) 2 = 41 ( 21 gt 2 )s= 41 HTherefore, the height from ground is GIVEN by,x=H−s=H− 41 H= 43 H |
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