1.

A body is projected with velocity .u. so that the maximum height is thrice the horizontal range. Then the maximum height is

Answer»

`(72 U^(2))/(145 G)`
`(6)/(SQRT(145))(u^(2))/(g)`
`(u^(2))/(2g)`
`(145)/(72)(u^(2))/(g)`

Answer :A


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