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A body is projected with velocity u=50ms at an angle of 37 degree |
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Answer» Explanation:H = u²(sinФ)²/2g = (50)²(3/5)²/20 = 2500*9/500 = 45After REACHING maximum height, the object should have a free fall .V²=u²+2*G*H' = 0 + 20*65 =1300So, v =√1300 = 10√13 |
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