1.

A body is projected with a velocity u at an angletheta with the horizontal . At t= 2s ,the body makes an angle 30^@ with the horizontal . 1 s later, it attainsits maximum height . Then

Answer»

`u=20 SQRT(3) m//s`
`THETA =60^@`
`theta= 45^@`
`u=(20)/sqrt(3) m//s`

Answer :A::B


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