A body is projected with a velocity of 98m/s find maximum height reach

1.	A body is projected with a velocity of 98m/s find maximum height reached
Answer» HEYA !!! This is your answer. Given : u = 98 m/s G = -9.8 m/s². ( As it is thrown upwards) v = 0 (As it will stop after reaching heighest point) Using 2gs = v² - u² 2 × -9.8 × s = - (98 × 98) s = (98 × 98)/(2 × 9.8) s = 98 × 5 s = 490 m. Now, Using v = u + at 0 = 98 - 9.8 × t t = 10 s Hope You Got It

A body is projected with a velocity of 98m/s find maximum height reached

Answer»

HEYA !!!

This is your answer.

Given :

u = 98 m/s

G = -9.8 m/s². ( As it is thrown upwards)

v = 0 (As it will stop after reaching heighest point)

Using

2gs = v² - u²

2 × -9.8 × s = - (98 × 98)

s = (98 × 98)/(2 × 9.8)

s = 98 × 5

s = 490 m.

Now, Using

v = u + at

0 = 98 - 9.8 × t

t = 10 s

Hope You Got It

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A body is projected with a velocity of 98m/s find maximum height reached​

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A body is projected with a velocity of 98m/s find maximum height reached