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a body is projected vertically upwards with velocity u crosses. it crosses point in its journey at a height h twice just after 1 and 7 second the value |
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Answer» h=ut− 2 1
gt 2
h=u(1)− 2 1
G=u− 2 g
.....(1) h=u(7)− 2 1
g(7) 2 =7u− 2 49g
.....(2) EQUATING (1) & (2) u− 2 g
=7u− 2 49g
24g=6u u=4g ⇒u=40 m/s |
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