A body is projected vertically upwards with a velocity of 40 m/s . Fin

1.	A body is projected vertically upwards with a velocity of 40 m/s . Find the maximum height reached by the body. (g = 10 m/s²)A) 80 mB) 20 mC) 30 mD) 40 m.(Need solution with explanation).
Answer» Given: A body is projected vertically upwards with a velocity of 40 m/s So, Initial velocity of the body ( u ) = 40 m/s Since, the body COMES to rest after REACHING maximum height Final velocity of the body ( v ) = 0 m/s The stone is thown upwards so g is considered as negative Acceleration due to GRAVITY acting on the body ( g ) = - 10 m/s² Let the maximum height reached by the body be 'H' m Using third equation of motion ⇒ v² - u² = 2gh ⇒ 0² - 40² = 2( - 10 )( h ) ⇒ 0 - 1600 = - 20h ⇒ 20h = 1600 ⇒ h = 1600 / 20 ⇒ h = 80 Therefore the maximum height reached by the body is 80 m ( A )

A body is projected vertically upwards with a velocity of 40 m/s . Find the maximum height reached by the body. (g = 10 m/s²)A) 80 mB) 20 mC) 30 mD) 40 m.(Need solution with explanation).

Answer»

Given:

A body is projected vertically upwards with a velocity of 40 m/s

So, Initial velocity of the body ( u ) = 40 m/s

Since, the body COMES to rest after REACHING maximum height

Final velocity of the body ( v ) = 0 m/s

The stone is thown upwards so g is considered as negative

Acceleration due to GRAVITY acting on the body ( g ) = - 10 m/s²

Let the maximum height reached by the body be 'H' m

Using third equation of motion

⇒ v² - u² = 2gh

⇒ 0² - 40² = 2( - 10 )( h )

⇒ 0 - 1600 = - 20h

⇒ 20h = 1600

⇒ h = 1600 / 20

⇒ h = 80

Therefore the maximum height reached by the body is 80 m ( A )

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