a body is projected vertically upwards with a speed 40m/s the distance travelled travelled by body in its last sec of its journey is

a body is projected vertically upwards with a speed 40m/s the distance

1.	a body is projected vertically upwards with a speed 40m/s the distance travelled travelled by body in its last sec of its journey is
Answer» v^2 = u^2 - 2as=> u = 0 BODY is at rest=> v= 40 m/s=> a= -10 m/s (g rounded to 10)(u is cancelled out, since it is 0)=> 40^2 = -2 * -10*s= 1600 = 20s=> s = 1600/20 = 80=> distance travelled = 80 m(ask any doubt you found in my EXPLANATION)

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a body is projected vertically upwards with a speed 40m/s the distance travelled travelled by body in its last sec of its journey is​

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a body is projected vertically upwards with a speed 40m/s the distance travelled travelled by body in its last sec of its journey is