A body is projected up such that its position vector varies with time as `r = { 3thati + (4 t - 5t^2)hatj}` m. Here, t is in seconds. Find the time and x-coordinate of particle when its y-coordinate is zero.

A body is projected up such that its position vector varies with time

1.	A body is projected up such that its position vector varies with time as `r = { 3thati + (4 t - 5t^2)hatj}` m. Here, t is in seconds. Find the time and x-coordinate of particle when its y-coordinate is zero.
Answer» Correct Answer - A::B::C::D y-coordinate of particle is zero when, `4t - 5t^2 = 0` `:. t = 0 and 0.8 s` `x = 3t` at t = 0, x = 0 and at t=0.8 s, x = 2.4 m.

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A body is projected up such that its position vector varies with time as `r = { 3thati + (4 t - 5t^2)hatj}` m. Here, t is in seconds. Find the time and x-coordinate of particle when its y-coordinate is zero.

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