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| 1. |
a body is projected in such way that its range and maximum height are equal. find the angle of projection |
| Answer» ANSWER given belowExplanation:givenhorizontal RANGE=u²sin 2Ф/g maximum height=u²sin² Ф / 2g horizontal range = 3× maximum height u²sin 2Ф / g =3×u²sin² Ф / 2g sin 2Ф=2sinФ.cosФ 2sinФ.cosФ= 3 / 2.sin²Ф tan Ф= 4 / 3 Ф=tan⁻¹( 4 / 3 )TO TYPE THIS I TOOK LIKE 2 HOURS. I HOPE IT HELPS U. MARK BRAINLIEST ANSWER IF U THINK THIS ANSWER US WORTH IT | |