A body is projected at t=0 with a velocity 10 ms−1 at an angle 60∘ with the horizontal. The radius of curvature of its trajectory at t=1 is R. Neglecting air resisteance and taking acceleration due to gravity g=10 m/s2, the value of R is:

A body is projected at t=0 with a velocity 10 ms−1 at an angle 60∘

1.	A body is projected at t=0 with a velocity 10 ms−1 at an angle 60∘ with the horizontal. The radius of curvature of its trajectory at t=1 is R. Neglecting air resisteance and taking acceleration due to gravity g=10 m/s2, the value of R is:
Answer» A body is projected at $t = 0$ with a velocity $10 {ms}^{- 1}$ at an angle $60^{\circ}$ with the horizontal. The radius of curvature of its trajectory at $t = 1$ is $R$ . Neglecting air resisteance and taking acceleration due to gravity $g = 10 {m/s}^{2}$ , the value of $R$ is:

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A body is projected at t=0 with a velocity 10 ms−1 at an angle 60∘ with the horizontal. The radius of curvature of its trajectory at t=1 is R. Neglecting air resisteance and taking acceleration due to gravity g=10 m/s2, the value of R is:

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