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A body is moving with uniform acceleration . Its velocity after 5 seconds is 25 m/s . Calculate the distance it will cover in 10th second |
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Answer» at t=5 sec INITIAL velocity u = 25m/s at t=8 sec final velocity v =34m/s the time INTERVAL for which the car travelled = 8-5 = t = 3 sec therefore the constant acceleration a is given by a= (v-u)/t a=(34-25)/3 a=3m/s^2 therefore initial velocity at t=0 u1=v-at u1=34-3(8) u1=10m/s the distance it will cover in the tenth SECONDS is equal to (the distance covered after 9 SECS) - ( the distance covered after 10 secs) we use the formula s=ut+1/2 at^2 therfore distance covered after 9 secs = 10(9) + 1/2(3)(9)^2=211.5m similarly distance covered after 10 sec = 10(10) + 1/2(3)(10)^2=250m therefore distance covered in the tenth second=250-211.5=38.5m |
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