1.

a body is dropped from a height h1.If it is rebounded to a height h2 then the coefficient of restitution

Answer»

When a body is dropped from a HEIGHT H1, The velocity before reaching the ground is

v = \sqrt{2gh1}

where g is the gravitational constant whose VALUE is 9.81 m2/sec

When the ball strikes the ground and bounces back to the height h2, The velocity just after impact was v' given as

v' = \sqrt{2gh2}

Coefficient of Restitution = \frac{\sqrt{v'}}{\sqrt{v} } = \sqrt{\frac{h2}{h1}}

Coefficient of Restitution = \frac{\sqrt{2gh2}}{\sqrt{2gh1} } = \sqrt{\frac{h2}{h1}}

Here is the SOLUTION, I have attached, hope it will help you.


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