A body is dropped froin height X, it reached the ground in 10 s. What

1.	A body is dropped froin height X, it reached the ground in 10 s. What is the velocitywhen it is touching the surface of the earth?
Answer» ANSWER: YES !!! Take your answer. The height of the tower is 20 m. Explanation: Given, u=0m/s v=20m/s g=10m/s 2 From 3rd equation of motion, 2gh=v 2 −u 2 h= 2g v 2 −u 2 h= 2×10 20×20−0×0 h=20m The height of the tower is 20m. Please mark as brilliant. Let's see how to mark in the FOLLOWING manner :- 1. On the Right corner at the end of answer we see a crown LIKE symbol. Please click on that. That marked as Brilliant. There are nearby the thanks and also near Rating :))

A body is dropped froin height X, it reached the ground in 10 s. What is the velocitywhen it is touching the surface of the earth?

Answer»

YES !!!

Take your answer.

The height of the tower is 20 m.

Explanation:

Given,

u=0m/s

v=20m/s

g=10m/s

From 3rd equation of motion,

2gh=v

−u

2×10

20×20−0×0

h=20m

The height of the tower is 20m.

Please mark as brilliant.

Let's see how to mark in the FOLLOWING manner :-

1. On the Right corner at the end of answer we see a crown LIKE symbol. Please click on that.

That marked as Brilliant.

There are nearby the thanks and also near Rating :))