Saved Bookmarks
| 1. |
A body initially at rest ( `theta = 0)` and `omega = 0` at `t = 0` ) and is accelerated over a circular path of radius `R = 1 m` as per the relation, `alpha = 120 t^(2) - 48 t + 16 "rad"//s^(2)`. At time t = 1 secA. angular velocity `omega = 32 "rad"//s`B. angular displacement `theta = 10` rad.C. tangential acceleration `a_(T0 = 88 m//s^(2)`D. centripetal acceleration `a_(c ) = 1024 m//s^(2)` |
|
Answer» Correct Answer - A::B::C::D `underset(0)overset(omega)int d omega = underset(0)overser(1)int alpha dt = underset(0)overset(1)int (120t^(2) - 48t + 16) dt` `underset(0)overset(theta)int d theta = underset(0)overset(1)int omega dt` `a_(T) = R alpha` `a_(C ) = omega^(2) R` |
|