Saved Bookmarks
| 1. |
A body having uniform acceleration of 10ms^(-2) has a velocity of 100ms^(-1). In what time, the velocity will be doubled? |
|
Answer» ong>Answer: Accelerarion (a)=10m/s^2 Final velocity(V) =100m/s It is understood that INITIAL velocity (u)= 0 According to the first kinematical equation, v = u +at 100 = 0+10t t=100/10 t=10 s…….(1) Similarly, When v is doubled= 2v =2×100= 200m/s, v=u +at 200= 0 +10t t= 200/10 t=20 s …..(2) THEREFORE, time taken to double the velocity =20 -10 =10 s Hence, the time taken to double the velocity is 10s. |
|