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A body having mass 'm' is moving at a velocity 'v' if its velocity is reduced half then what will be its kinetic energy? Please give a specific solution. |
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Answer» Given: Initial velocity =v; Final velocity = 3V Initial kinetic energy k 1 = 21 ×m×v 2 Final kinetic energy k 2 = 21 ×m×( 3v ) 2 = 91 × 21 MV 2 Change in kinetic energy = 21 mv 2 − 91 × 21 mv 2 = 21 mv 2 (1− 91 )= 98 × 21 ×mv 2 = 98 × Initial kinetic energy. |
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