A body having an excess of 10 ^6 electrons is placed in an electric fi

1.	A body having an excess of 10 ^6 electrons is placed in an electric field of 1000 n /c towards east. find out the magnitude and direction of the force acting on the body.
Answer» Answer: Electric force, F = 1.6 × 10⁻¹⁰ N and its direction is inwards Explanation: It is given that, NUMBER of electrons, e = 10⁶ TOTAL charge, $<klux>Q</klux>=1.6\times 10^{-19}\times 10^6\ C=1.6\times 10^{-13}\ C$ Electric field, E = 1000 N/C Electric force is given by the product of electric charge and electric field. i.e. F = q E $F=1.6\times 10^{-13}\ C\times 1000\ N/C$ $F=1.6\times 10^{-10}\ N$ As the electrons are negatively charged particles. The direction of electric filed for electrons is NEGATIVE.

A body having an excess of 10 ^6 electrons is placed in an electric field of 1000 n /c towards east. find out the magnitude and direction of the force acting on the body.

Answer»

Answer:

Electric force, F = 1.6 × 10⁻¹⁰ N and its direction is inwards

Explanation:

It is given that,

NUMBER of electrons, e = 10⁶

TOTAL charge, $<klux>Q</klux>=1.6\times 10^{-19}\times 10^6\ C=1.6\times 10^{-13}\ C$

Electric field, E = 1000 N/C

Electric force is given by the product of electric charge and electric field.

i.e. F = q E

$F=1.6\times 10^{-13}\ C\times 1000\ N/C$

$F=1.6\times 10^{-10}\ N$

As the electrons are negatively charged particles. The direction of electric filed for electrons is NEGATIVE.

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