A body float with (1/3) of its volume outside water and (3/4) of its v – InterviewSolution

1.

A body float with (1/3) of its volume outside water and (3/4) of its volume outside another liquid the density of another liquid

Answer»

Answer:

Volume = V

density= d

density of water =q = 1000 kg/m3

weight in AIR = w= Vgd

Buoyant force= (2V/3)qg

density of other liquid =p

volume of body inside water= V- 3V/4= V/4

buoyant force = (V/4)pg

as in both SITUATION the body will float so,

(2V/3)qg = (V/4)pg

p = 8q/ 3

p = 8 X 1000/3

p= 8 /3 x 10³

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