A body falls freely from a tower and travels a distance of 40 m in its

1.	A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height ofthe tower is (take g = 10 m/s^2):
Answer» we use the third EQUATION h=ut+1/2gt^2 u=0 m/s g=10 m/s^2 t=2 sec h=? h=ut+1/2at^2 or, h=0×2+1/2×10×2×2 or, h=0+5×4 or, h=20 m so, the height of the TOWER is 20 m

A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height ofthe tower is (take g = 10 m/s^2):

Answer»

we use the third EQUATION h=ut+1/2gt^2

u=0 m/s

g=10 m/s^2

t=2 sec

h=?

h=ut+1/2at^2

or, h=0×2+1/2×10×2×2

or, h=0+5×4

or, h=20 m

so, the height of the TOWER is 20 m

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A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height ofthe tower is (take g = 10 m/s^2):​

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A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height ofthe tower is (take g = 10 m/s^2):