A body falling vertically .downwards explodes into two equal fragments when it is at a height of 200 m and has a downward velocity of ,6just after the explosion one pf the fragments is seen to move .downward with a velocity of 8 ms^(-1) .Calculate the position of the centre pf mass of the system 5 s after ,the explosion.

A body falling vertically .downwards explodes into two equal fragments

1.	A body falling vertically .downwards explodes into two equal fragments when it is at a height of 200 m and has a downward velocity of ,6just after the explosion one pf the fragments is seen to move .downward with a velocity of 8 ms^(-1) .Calculate the position of the centre pf mass of the system 5 s after ,the explosion.
Answer» Solution :The EXPLOSION is not due to any EXTERNAL force. So after explosion ALSO the CM continues to move as if there was no explosion. Distance travelled after 5s is `y=y_(0) + (1//2) gt^(2) = 6 XX 5 +(1//2) 9.8 xx 25 y=152.5 m`. So C.M. is at a distance 200-152.5 = 47.5 m above the ground.