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A body falling freely to a height of 10m goes into sand 1 mm. The retardation of the body in sandis :(a) 1000 g(b) 100 g(c) 10 g(d) 1 gif anyone know the solution please explain it ​

Answer»

² - u²2×9.8×1000 = v²9800×2 = v²v = √19600 = 140 mm/s2as = v² - u²2×a×1 = 0 - 196002a = -19600a = -9800mm/sAcceleration = -9.8m/s



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