A body executing shm completes 120 oscillations per minute. If the amplitude of oscillations is 6 cm, find the velocity and acceleration of the particle when it is at a distance of 4 cm from the mean position?

A body executing shm completes 120 oscillations per minute. If the amp

1.	A body executing shm completes 120 oscillations per minute. If the amplitude of oscillations is 6 cm, find the velocity and acceleration of the particle when it is at a distance of 4 cm from the mean position?
Answer» SOLUTION :`v=omegasqrt(a^2-y^2)=2pixx(120//60)SQRT(6^2-4^2)=0.56 m//s.alpha=omega^2y = (4pi^2) xx4 =63.1 MS^(-2)`