A body dropped from the top of tower takes 4 sec to hit the ground.How

1.	A body dropped from the top of tower takes 4 sec to hit the ground.How much time does it takes to cover second half tower (g =10 m/s^2)
Answer» ANSWER : Time taken by body to hot the ground = 4s We have to find time taken by body to cover second half of the tower $.$ ★ First of all we need to find HEIGHT of the tower. For a body falling freely under the action of gravity, g is taken positive. For FREE falling motion, u = zero ➝ H = ut + 1/2 gt² ➝ H = 0 + 1/2 (10)(4)² ➝ H = 1/2 (160) ➝ H = 80 m Now let's find time taken by body to cover first half of the tower. Height of first half will be 40m. ➝ H/2 = ut₁ + 1/2 gt₁² ➝ 40 = 0 + 1/2 (10)(t₁)² ➝ 40 = 5t₁² ➝ t₁² = 8 ➝ t₁ = 2.82 m Time taken by body to cover second half : ➝ t = t₁ + t₂ ➝ 4 = 2.82 + t₂ ➝ t₂ = 1.18 s ∴ Body will take 1.18s to cover second half of the tower.

A body dropped from the top of tower takes 4 sec to hit the ground.How much time does it takes to cover second half tower (g =10 m/s^2)

Answer»

ANSWER :

Time taken by body to hot the ground = 4s

We have to find time taken by body to cover second half of the tower $.$

★ First of all we need to find HEIGHT of the tower.

For a body falling freely under the action of gravity, g is taken positive.

For FREE falling motion, u = zero

➝ H = ut + 1/2 gt²

➝ H = 0 + 1/2 (10)(4)²

➝ H = 1/2 (160)

➝ H = 80 m

Now let's find time taken by body to cover first half of the tower.

Height of first half will be 40m.

➝ H/2 = ut₁ + 1/2 gt₁²

➝ 40 = 0 + 1/2 (10)(t₁)²

➝ 40 = 5t₁²

➝ t₁² = 8

➝ t₁ = 2.82 m

Time taken by body to cover second half :

➝ t = t₁ + t₂

➝ 4 = 2.82 + t₂

➝ t₂ = 1.18 s

∴ Body will take 1.18s to cover second half of the tower.

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