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A body covers 4 m in 3rd second and 12 m in 5th second in uniformly accelerated motion. The uniform acceleration of the body is?? |
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Answer» tion:We KNOW that distance Travelled by uniformly accelerated BODY in n th s is given bySn =u+ 1/2 a(2n−1), where a is the acceleration of the body and u is the initial velocity it is given that S n =4s at n=3⟹4=u+ 25a .............. eq(1)S n =12 at n=5s⟹12=u+ 29a ............... eq(2)SOLVING eq(1) and eq(2), we geta=4m/s 2 and u=−6m/sNow we have to FIND velocity at t=5swe know that v=u+at⟹v=−6+(4×5)=14m/s ⟹S=14×3+1/2 4(3^2)=60mhope this will help you |
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