1.

A body cools from 60^(@) C to 50^(@) C in 6 minutes, the temperature of the surroundings being 25^(@) C. What will be its temperature after another 6 minutes ?

Answer»


SOLUTION :`(60-50)//5alpha[(60+50)//2]-25, (50-theta)//6alpha[((50+theta)/2)-25],theta=41.67^(@)C`


Discussion

No Comment Found