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A body cools from `50^(@)C` to `40^(@)C` in 5 min. The surroundings temperature is `20^(@)C`. In what further times (in minutes) will it cool to `30^(@)C` ?A. 5B. `15//4`C. `25//3`D. 10 |
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Answer» Correct Answer - C (3) `(Delta theta)/(Delta t) = - k (bar theta - theta_(0))` `(50 - 40)/(5) = - k ((50 + 40)/(2) - 20)` `2 = - k xx 25 implies K = - (2)/(25)` `(40 - 30)/(t) = - k ((40 + 30)/(2) - 20)` `(10)/(t) = (2)/(25) (15) implies t = (25)/(3)` min |
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